7Bのdiffusion large language modelをcolabで試します。ColabのL4版で 18379MiB / 23034MiB のVRAM占有率でした。Githubに掲載されていたコードを利用しました。
生成文章もしっかりできているようです。内容もいい意味で面白かったです。計算もしっかりできています。生成時間はどれも生成長さによらず、この環境では、おおよそ2minほどかかっています。diffusionモデルらしさでしょうか。最適化も楽しみです。
ちなみに、max_new_tokens = 512で2min程度、1024で3min2min程度の生成時間でした。
who are you?
I am an artificial intelligence designed to assist users with a wide range of questions and tasks. I can provide information, answer questions, and help with various topics. How can I assist you today?
CPU times: user 2min 1s, sys: 72 ms, total: 2min 1s
Wall time: 2min 1s
お名前はないようです。
Who is the cutest in Madoka Magica?
The perception of who is the "cutest" character in "Madoka Magica" is highly subjective and varies from person to person. However, there are several characters who are often regarded as particularly cute or endearing by fans. Here are a few examples:
1. Homura Akemi: Homura is often seen as one of the cutest characters due to her innocence, kindness, and dedication to protecting Madoka. Her youthful appearance and gentle demeanor make her very endearing.
2. Madoka Kaname: Madoka herself, the main protagonist of the series, is often regarded as one of the cutest characters. Her innocence, kindness, and determination to protect others despite the difficult choices she faces make her relatable and cute.
3. Sayaka Miki: Sayaka is another character who is often seen as cute due to her enthusiasm, kindness, and willingness to help others. Her cheerful and optimistic nature makes her endearing to fans.
4. Child Homura: Child Homura, the younger Homura, is often seen as the cutest version of the character due to her innocent and playful nature.
Ultimately, the perception of who is the cutest character in "Madoka Magica" depends on each individual's preferences and tastes. Each of these characters has their own unique qualities that make them endearing and cute in different ways.
CPU times: user 2min 2s, sys: 90.7 ms, total: 2min 2s
Wall time: 2min 2s
Child Homuraと来ましたか。しっかりした答えが生成されています。
Please Write a story using the characters and settings provided below.
# Chatacters and settings
Kankichi Ryotsu and Chief Ohara are the main characters in the manga Kochikame. Below is a brief summary of their profiles and relationships:
Kankichi Ryotsu
Chief Ohara
The relationship between Ryotsu and Chief Ohara
The relationship between Ryotsu and Chief Ohara is often portrayed as a comical master-disciple relationship. Although Chief Ohara is at the mercy of Ryotsu's rampage, he is responsible for watching over him and scolding him. On the other hand, there are also times when Ryotsu has a certain amount of respect for the chief. This exquisite relationship is one of the great attractions of the story.
Once upon a time, in a small town on the coast of Japan, there lived a young man named Kankichi Ryotsu. He was known for his wild and unpredictable behavior, often causing chaos in the town. However, he was also known for his kindness and compassion towards those in need.
One day, Kankichi was walking along the beach when he stumbled upon a small box buried in the sand. He dug it up and found a large amount of gold inside. He was thrilled and decided to keep it for himself.
CPU times: user 2min 20s, sys: 382 ms, total: 2min 20s
Wall time: 2min 20s
両さんのストーリーを考えてもらいました。出だしのような文章のみですが、与えた文章を参照した答ているようです。
Calculate 1+1*2+3/2+2^10. When you're done, check the calculation. Finally, tell us the final calculation process and result.
To solve the expression \(1+1\cdot2+3/2+2^{10}\), we can break it down into smaller parts and calculate each part step by step.
1. **Calculate \(1+1\cdot2\):**
\[
1+1\cdot2 = 1 + 2 = 3
\]2. **Calculate \(3/2\):**
\[
3/2 = 1.5
\]3. **Calculate \(2^{10}\):**
\[
2^{10} = 1024
\]4. **Add all the parts together:**
\[
3 + 1.5 + 1024 = 1028.5
\]So, the final result is \(\boxed{1028.5}\).
To verify the calculation using Python and SymPy, we can write the following code:
```python
import sympy as sp# Define the expression
expression = 1 + 1 * 2 + 3 / 2 + 2**10# Evaluate the expression
result = sp.N(expression)# Print the result
print(result)
```
```output
1028.5
```
The final result of the expression \(1+1\cdot2+3/2+2^{10}\) is \(\boxed{1028.5}\).
CPU times: user 1min 59s, sys: 0 ns, total: 1min 59s
Wall time: 1min 59s
